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>Zeros A and B have a linear factor to an odd power.
>Zero C has a linear factor to an even number.
>Got it? Got it. I'm moving along now.
>I want to finish this already too, you know. I need to get back to watching the participants before my boredom kills me a second time.

0 3
2020-05-22

>So far, we know that the leading coefficient's power is even and higher than three, and that there are 3 zeros.
>We're not done yet! We can also determine the powers of the zeros as well.
>At A and B, the line crosses the x-axis, while at C, it bounces.

1 2
2020-05-22

>The "it" is the zeros. We determine the multiplicity by looking at the power of the linear factors.
>For (x-2)^2, (x-2) is the linear factor.
>We won't take a look at the magnitude, we'll only take a look at whether it's even or odd, black or white, dead or alive.

0 0
2020-05-22

>x=-3, 2, -1... Those are the zeros.
>When you plug in either of those, one of the factors, (x+3)(x-2)(x+1), will be canceled into a 0. It's a given, but 0 times anything is zero.
>For example, if we plugged in x=-3...
y=((-3)+3)((-3)-2)((-3)+1)
y=(0)(-5)(-2)=0

0 1
2020-05-22

>Surprised? My innate floormaster spirit kicked in, you better forgive him or he won't forgive you! Haha.
>Yes though, it can intersect the x-axis any less than 6 but no more than 6 as well. The possibilities are finite.
>Here in the example, there will be only 3 zeros.

0 1
2020-05-22

>Continuing on, it's in factored form. Factored form is significantly more helpful since it gives us the zeros on sight.
>A "zero" is the x-value that when plugged into the function, will yield a y-value of zero. Graphically, they're intersections through the x-axis.

0 0
2020-05-22

thinking about layers concept art hair;; also zeros here

87 236
2020-05-22

I did submission on this, I needth' them votes, Doctahs in among my followers!

https://t.co/yj760m91Fp

Search Author : KZMShin
Search Work : [ZERO SANITY]





Please do! And thank you for those who took their time on this request!

1 1
2020-05-19