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i^i = e^(i*ln(i)) = e^(-pi/2) ≈ 0.2 Header by @Minerea_Arts
hackerdragon.ch/refi^i = e^(i*ln(i)) = e^(-pi/2) ≈ 0.2 Header by @Minerea_Arts
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Happy pride month everyone!
We stand proud in what we are.
Arts by the amazing @fluffylunarii
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Happy #InternationalAsexualityDay!
:D
Art by the amazing @TwilitYeen
ö..ö https://t.co/ItLCaZafR5
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