# p5js creativecoding stablediffusion zrveroc define つぶやきglsl sizzlegang nft nfts nftdrop nftcommunity nftcollectors nftcollectibles nftcollection nftinvestor crypto cryptoart eth bacon opensea openseanft openseanftart drake sqrt69 fractal つぶやきprocessing fbb fff fractals generative digitalart processing

Inkscape1.3は治ったけど，Twitter下書きしてないと返信書き途中きえるわ昔に戻ってる感．長さ固定が１，添付画像が２「m=sqrt(3)/2, t=Tan[pi/72], (d/dk)[sqrt(1-k^2)+(k*(1-t^2)-m*(1+t^2))/2/t]=0」 https://t.co/4Pp77A0mJ4 k=Cos[π/36]，一点固定極大斜矢弦が３，２つの弓形内の線分を足した最大

0 0
2024-01-14

생일 기념으로 넣은 것 랴(@ Lia___S2 )과 @
squrt1∞(@ sqrt100)님 커미션~

1 7
2023-03-03

. 『sqrt(佐久間まゆ*夢見りあむ)』
(sqrt(Mayu Sakuma*Riamu Yumemi))

1 2
2023-02-07

自動生成された数式による絵画。🖼️
今回の数式はこれ atan(_a) + acos(_a) * pow(_a, 2) % asin(_a) * pow(_a, -2) % sqrt(_b) - asin(_b)
関数をめちゃくちゃに組み合わせてるだけだから、面白いと思える絵が出るのは50回に1回ぐらい。😂

2 10
2022-11-02

I have come here to explore function spaces & strain models, ...and I'm all out of function spaces.

Same prompt: "$$f = {1\over 2\pi} \sqrt{{k \over m}}$$ fantasy art"

0 3
2022-09-29

sqrt(cos(x))*cos(300x)+sqrt(abs(x))-0.7)*(4-x*x)^0.01 sqrt(6-x^2)

(Oc, not bl)
Fred, Seb

2 5
2022-05-27

WolframAlpha「(sqrt(a^2+b^2)-a)*(sqrt(a^2+b^2)+b+a)^2-(sqrt(a^2+b^2)+a)*(sqrt(a^2+b^2)+b-a)^2」 https://t.co/rLxZysnQiI ≡0、「(1-cos[x])*(1+sin[x]+cos[x])^2-(1+cos[x])*(1+sin[x]-cos[x])^2」 https://t.co/XrLhrmn3eQ ≡0。という恒等式が一見不明だったけどx=2*tとでもすれば、2*sin^2 [

0 0
2022-05-19

F d=max(d,(1.2-length(sqrt(abs(mod(p*s,2.)-1.))))/s);p+=s*=1.7
float l=.01,d=l,s=.3,i;vec3 O=vec3(s,1,t),p,D=vec3((FC.xy*2.-r)/r.y,s)*rotate3D(t,O.xxy);for(;i<1.&&d>1e-4;i+=.01){p=O+D*l;d=0.;s=3.;F;F;l+=F;}F;o.rgb+=hsv(l,.2/l,i+d*s);

https://t.co/hlJ5Aze6ex

5 16
2022-04-23

1 - 1,444 --> sqrt(−0.444) =
Keep it Real

0 0
2022-04-16


(sqrt((1+sqrt(2))/8)+sqrt((1+sqrt(2))/8)i)(z^2+1/z^2)

9 35
2021-10-27

setup=_=>{createCanvas(w=720,w,WEBGL),shader(createShader(`attribute vec3 a${c};void main(){gl_${c}=vec4(a${c},1.)*2.-1.;}`,`precision lowp float;void main(){vec2 p=sqrt(gl_FragCoord.xy);gl_FragColor=vec4(9./dot(cos(p),p),p,1.);}`)),rect(0,0,w)};c="Position";//#つぶやきProcessing

1 12
2021-09-13

float i,d=.1,s;vec3 p,n=vec3(-3);for(i=0.;i++<64.&&d>1e-4;){p=vec3((FC.xy-r*.5)/r.y,.3)*s*4.;p.z+=8.;p.xz*=rotate2D(mod(t*.2,5.));for(int j;j++<6;){p=abs(p)-1.;d=1.-sqrt(p.y)-.1;d>0.?d-=min(d-.1,max(p.y+.2,dot(p.x,p.z))):d;}s+=d;}o+=vec4(5,3,3,1)/i;

3 9
2021-09-03

size(720,720,P2D)
frameRate(1)
f=open("a","w")
f.write("void main(){vec2 v=(gl_FragCoord.xy-360)/360.;float q=atan(v.x,v.y);float a=abs(cos(5.*q)*sin(q+sqrt(length(v))*16))*.8;gl_FragColor=vec4(1.-vec3(0,a+.1,a+.3),1);}")
f.close()
filter(loadShader("a"))

5 21
2021-06-29

Well if we do the math
Substitute = cos\alp,\alp∈[0:;π] \Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+ 1−x 2 ​ ∣= 2 ​ (2x 2)

= You lonely asf

0 1
2021-02-14

setup=_=>{createCanvas(w=720,w)//#つぶやきProcessing
C=['#fbb','#694','#333','#fff']
a=new Date()%2
fill(C[a])
stroke(C[a+2])
v=40
u=10*sqrt(3)
f=s=>triangle(0,0,20,0,30,s*u)
for(k=v*v;k--;){
push()
translate(k%v*30,u*2*(k/v|0)-k%v*u)
for(i=6;i--;)rotate(PI/3),f(1),f(-1)
pop()}
}

5 11
2020-09-05

. Perhaps sin(sin(cos((x^3-y^3)))+abs(sin(x)+hypot(x,y)))-atan(sin(atan(avg(x,y))))+abs(sqrt(x))*c*abs(x*x-x*x).

0 1
2020-08-04

菱形十二面体を置くための台
空間充填したい時あると便利かも
z = ( acos( cos(x) ) + acos( cos(y) ) ) / sqrt(2)

0 2
2020-07-28

This was fun. Thanks ! These are all the roots of quadratics with integer coef from -200 to 200. The colored versions color the point by the size of the sqrt(discriminant). Zoom ins are the last two images. ( https://t.co/9MruLhzauW )

3 20
2020-05-27